So, you if last thing after the . is a model ==> So, if the last thing
after . is a model

On Wed, Nov 11, 2015 at 11:11 AM, Ernesto Reinaldo Barreiro <
reier...@gmail.com> wrote:

> I see your point... I do not know if such a change could break existing
> applications. Thought I guess not. So, you if last thing after the . is a
> model, i.e. a.b -> b, is a model automatically call b.getObject
>
> On Wed, Nov 11, 2015 at 11:02 AM, Tom Götz <t...@decoded.de> wrote:
>
>> Yeah this will work, thanks. I did fear that somebody came around with
>> that proposal ;-)
>>
>> It would feel more „natural" if PropertyResolver/PropertyModel would care
>> about calling model.getObject() (if the target value is an instance of
>> IModel) though.
>>
>>    Tom
>>
>>
>> > On 11.11.2015, at 10:51, Ernesto Reinaldo Barreiro <reier...@gmail.com>
>> wrote:
>> >
>> > What happens if you user "someModel.object"?
>> >
>> > On Wed, Nov 11, 2015 at 10:48 AM, Tom Götz <t...@decoded.de> wrote:
>> >
>> >>
>> >> Hi there,
>> >>
>> >> I have the following situation:
>> >>
>> >>
>> >> MyClass extends Panel {
>> >>
>> >>   private IModel<String> someModel;
>> >>
>> >>   MyClass(String id) {
>> >>      super(id);
>> >>      add(new Label(„label“, PropertyModel.of(this, „someModel“));
>> >>   }
>> >>
>> >> }
>> >>
>> >>
>> >> But instead of displaying someModel’s modelObject, the Label displays
>> >> someModel.toString(), which is how PropertyResolver is implemented
>> (does
>> >> not check if value instance IModel …). Is there a best practice how to
>> >> handle such constructs?
>> >>
>> >> Cheers,
>> >>   Tom
>> >>
>> >>
>> >
>> >
>> > --
>> > Regards - Ernesto Reinaldo Barreiro
>>
>>
>>
>>
>>
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>
>
> --
> Regards - Ernesto Reinaldo Barreiro
>



-- 
Regards - Ernesto Reinaldo Barreiro

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