Hi!
Caleb James DeLisle wrote:
> There are various ways with different levels of code cleanliness
> since all user names start off with 'XWiki.' you could use
> $context.getUser().substring(6)
>
> If you're looking for the user's "common name" instead of the user name, you
> might want to look at
> $xwiki.getUserName
> http://maven.xwiki.org/site/xwiki-core-parent/xwiki-core/apidocs/com/xpn/xwiki/api/XWiki.html#getUserName%28java.lang.String%29
>
>
Please, as $context is a class and getUser() is a method of that class,
what is .substring()?
Let's call *name* to the answer to the previous question. Please, where
are the possible *name* that could be used with a given method of a
given class?
I'm browsing XWiki API looking for a way of doing the same you have
proposed with .getUser() but with the name of a document. That is, how
to get Document instead Space.Document.
For instance, here...
#set($results=$xwiki.searchDocuments($query))
#foreach($item in $results)
#set ($itemdoc = $xwiki.getDocument($item))
* [$itemdoc>$itemdoc], ~~$itemdoc.display('Genrus')
$itemdoc.display('Species')~~<br/>
$itemdoc shows Space.Document. How do I get just Document?
Please, excuse me if this questions are too basic! Thanks for your help!
--
Ricardo RodrÃguez
CTO
eBioTIC.
Life Sciences, Data Modeling and Information Management Systems
_______________________________________________
users mailing list
[email protected]
http://lists.xwiki.org/mailman/listinfo/users
