*Measured* air pressure at a given time and place has a well defined meaning. 
However, "average air pressure" is poorly defined.  The value "760 mm Hg" is 
little more than a conventional common reference value, which is seldom 
realized naturally with great precision anywhere at any time.

Calculation of "average air pressure" depends strongly on the *definition* used 
for the calculation and is of questionable value.

---- Original message ----
>Date: Fri, 12 Feb 2010 04:32:26 -0800 (PST)
>From: "John M. Steele" <[email protected]>  
>Subject: [USMA:46601] Re: Average air pressure  
>To: "U.S. Metric Association" <[email protected]>
>Cc: "U.S. Metric Association" <[email protected]>
>
>   I am amazed it agrees as well as it does; I
>   CERTAINLY would not expect five digits of precision.
>    
>   While there is nothing inherently wrong with naive
>   models, (hell the standard atmosphere is a naive
>   model), you have repeatedly replaced detail with
>   averages and assumed it all averages out.  Gravity
>   varies around ±½% from pole to equator.  The earth
>   is an ellipsoid, the average radius you used is
>   correct for volume, not necessarily for surface
>   area.  As the atmosphere is a gas, and can move,
>   variations in the vertical temperature profiles are
>   critical to the local pressure (and cause variation
>   day to day).  Finally the assumption that averaging
>   works has  a flaw that there is (mostly) sea below
>   sea level, while mountains intrude into the air
>   space and displace air all over the world; the
>   assumption that a uniform mass of air is uniformly
>   resting on a sphere has a BUNCH of problems.  (I
>   have NO idea how to solve them all.)
>    
>   We know air pressure varies day to day with weather,
>   however, the total atmosphere is relatively
>   constant.  I believe a better way to proceed is to
>   average a large number of simultaneously
>   measurements at (or corrected to) sea level, all
>   over the earth.  The stations should be chosen to
>   represent a good sampling plan.  It is certainly
>   true that the overly precise 101.325 kPa is nothing
>   but 760 mm Hg expressed in SI.  Wikipedia's article
>   on the atmosphere has a nice map of 15 year average
>   air pressure in December and June,
>   http://en.wikipedia.org/wiki/Atmospheric_pressure
>    
>   I think it shows two things:
>   *The average is NOT 101.325 kPa everywhere
>   *The standard value of 101.325 kPa is much more in
>   the middle of data than your value.
>
>     ------------------------------------------------
>
>   From: Pat Naughtin
>   <[email protected]>
>   To: U.S. Metric Association <[email protected]>
>   Cc: U.S. Metric Association <[email protected]>
>   Sent: Fri, February 12, 2010 12:17:05 AM
>   Subject: [USMA:46597] Average air pressure
>   Dear Bill and All,
>   I have had another thought on finding the average
>   pressure at (or near) the surface of the Earth. As
>   you will see, I am trying to derive the average by
>   calculation. Our previous correspondence is below. I
>   would appreciate any thoughts you might have on this
>   way of proceeding and particularly on my
>   calculations.
>
>   National Center for Atmospheric Research
>
>   According to the National Center for Atmospheric
>   Research, "The total mean mass of the atmosphere is
>   5.1480 x 1018 kg with an annual range due to water
>   vapor of 1.2 or 1.5 x 10^15 kg depending on whether
>   surface pressure or water vapor data are used;
>   somewhat smaller than the previous estimate. The
>   mean mass of water vapor is estimated as 1.27 x
>   10^16 kg and the dry air mass as 5.1352 ±0.0003 x
>   10^18 kg."
>
>   Calculation
>
>   Mass of Earth's atmosphere                        
>                                       = 5.1480 x 10^18
>   kilograms
>
>   Weight of atmosphere = mg = m x 9.80665 m/s2
>                                = 50.48463 x 10^18
>   newtons
>
>   Surface area of Earth = 4 π r2 = 4 x π x (6.378
>   137 x10^6)^2 m         = 511.207 8 x 10^12 square
>   metres
>
>   Average pressure at sea level (Force ÷ area)      
>                                 = 98.755 58 x 10^3
>   pascals = 98.756 kPa
>
>   Irrelevant information about the atmosphere and the
>   Earth
>
>   The average mass of the atmosphere is about 5
>   teratonnes (= 5.1480 x 10^18 kilograms).
>
>   The average mass of the Earth is about 6 zettatonnes
>   (= 5.9742 × 10^24 kilograms).
>
>   The proportion of the whole Earth to its atmosphere
>   is roughly 1 000 000 to 1, that is if the atmosphere
>   was valued at 1 cent then the Earth would be valued
>   at $10 000.00.
>
>   Cheers,
>    
>   Pat Naughtin
>   Author of the ebook, Metrication Leaders Guide, that
>   you can obtain
>   from http://metricationmatters.com/MetricationLeadersGuideInfo.html 
>   PO Box 305 Belmont 3216,
>   Geelong, Australia
>   Phone: 61 3 5241 2008
>   Metric system consultant, writer, and speaker, Pat
>   Naughtin, has helped thousands of people and
>   hundreds of companies upgrade to the modern metric
>   system smoothly, quickly, and so economically that
>   they now save thousands each year when buying,
>   processing, or selling for their businesses. Pat
>   provides services and resources for many different
>   trades, crafts, and professions for commercial,
>   industrial and government metrication leaders in
>   Asia, Europe, and in the USA. Pat's clients include
>   the Australian Government, Google, NASA, NIST, and
>   the metric associations of Canada, the UK, and the
>   USA. See http://www.metricationmatters.com/ to
>   subscribe.
>   On 2009/12/05, at 08:51 , Bill Hooper wrote:
>
>     On  Dec 4 , at 11:38 AM, Pierre Abbat wrote (in
>     response to my earlier note):
>
>         (I wrote) Normal or
>
>         average atmospheric pressure is about 101.3
>         kPa. (There may be different
>
>         standards for identifying "normal" or
>         "average" air pressure.)
>
>       (Pierre replied)
>       101.325 kPa, to be exact, is the standard.
>
>     The value of 101.325 kPa is the exact value (the
>     "standard") specified by CGPM for the standard
>     atmospheric pressure, as Pierre correctly points
>     out. That value is as close to a universal value
>     as is possible.
>     In addition, however, there are other
>     circumstances where different standards are used.
>     Here are two I've encountered (from Wikipedia):
>
>       ... International Union of Pure and Applied
>       Chemistry (IUPAC) recommended that for the
>       purposes of specifying the properties of
>       substances, “the standard pressure” should
>       be defined as precisely 100 kPa ... rather than
>       the 101.325 kPa value of “one standard
>       atmosphere”. ... For natural gas, the
>       petroleum industry uses a standard temperature
>       of 15.6 °C (60.1 °F), pressure 101.56 kPa
>       (14.730 psi). (air pressure)
>
>     The CGPM standard is probably more precise than is
>     reasonable for many uses, such as reporting air
>     pressure in weather reports. For such
>     measurements, a rounder value of 101.3 kPa or even
>     101 kPa might be suitable as a state "normal" or
>     "average".
>     Certainly, atmospheric pressure is affected by
>     altitude and other factors. For specific locations
>     or specific special conditions, the CGPM standard
>     atmosphere may not be too close to the actual
>     average of the ambient pressure.
>     This is not meant to be argumentative. I recognize
>     the value of 101.325 kPa as the best value to use
>     for most technical purposes. I just felt it was
>     necessary to indicate in my note that there are
>     different possible averages or normal values that
>     might be used.
>     Regards,
>     Bill Hooper
>
>     ==============================
>     If you have not already done so, 
>     please note my new email address:
>
>          [email protected]
>
>     (Old address will still work OK temporarily.)


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