A question on how sin(Infinity) or sin(Nan) is handled.
It seems that for these values, we have to go all the way through to the
Payne-Hanek routine in C to get it to return NaN, which is then passed into
the
kernel routines.
While NaN and Infinity are relatively rare, it's been my experience that
once
NaN is generated, it just propagates everywhere forever, so now all trig
functions will be blazingly slow.
Would it make sense to add the special case to REMPIO2 instead? And maybe
inform
MathSin, MathCos, and MathTan that REMPIO2 returned NaN so the kernel
routines
aren't called?
https://codereview.chromium.org/411263004/
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