Comment #1 on issue 3495 by [email protected]: Math.tanh issues
http://code.google.com/p/v8/issues/detail?id=3495
Let D(x) = Math.expm1(x) and assume expm1(x) is accurate.
Then
tanh(x) = -D(-2*x)/(2+D(-2*x))
For |x| >= about 18.72, you can just return sign of x.
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