Comment #8 on issue 3852 by impinball: v8 module operation is not
compatible with ECMA SCRIPT
https://code.google.com/p/v8/issues/detail?id=3852
#5
I'm pretty sure that the formula can overflow. Is that the case with
arbitrary precision arithmetic?
C's fmod is much more likely to keep precision than that formula, despite
theoretical equivalence.
For a similar reason, the former of these two is preferred:
/-------------
| / x \ 2
hypot(x, y) = |x| \ | 1 + | --- |
\| \ y /
/---------
| 2 2
hypot(x, y) = \| x + y
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