Danno, thanks for the review. All comments are addressed. Please take
another
look.
On 2013/07/31 09:30:55, danno wrote:
Yes, this sounds fine.
However, I still think in this case you will have to have:
If I understand the codes right, the receiver is at argc offset of the last
argument. The 1 is for return address in the original code.
inline Operand StackOperandForReceiver(int argc) {
return StackOperandForReversedArgument(argc + 1);
}
https://codereview.chromium.org/21123008/
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