Comment #2 on issue 2820 by [email protected]: Content of variables not
used in closures cannot be inspected
http://code.google.com/p/v8/issues/detail?id=2820
Try then:
(function(){
var c = 10;
(function(){
debugger;
console.log(5);
})();
})();
Now you cannot find c anywhere.
From a functional point of view there is no difference to have or not c
accessible in the function if c is not used. But it makes a difference in
debug. In order to see the value I need to go an modify the javascript.
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