So I can test if something is a built in prototype as so: if (thing->IsArray() && thing->GetPrototype()->ToObject()->GetPrototype()->IsNull()) // yes.
But, thing->IsObject() breaks down with this test, which would theoretically look like this: if (thing->IsObject() && thing->GetPrototype()->IsNull()) // yes. Since Object.create(null) will also pass this test. Is there something else I could do to determine if this is a Object.prototype? (I can't compare because the objects may be coming from different contexts). -- -- v8-users mailing list [email protected] http://groups.google.com/group/v8-users --- You received this message because you are subscribed to the Google Groups "v8-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
