On Fri, May 8, 2015 at 2:57 AM, Francisco Tolmasky <[email protected]> wrote:
> So I can test if something is a built in prototype as so:
>
> if (thing->IsArray() &&
> thing->GetPrototype()->ToObject()->GetPrototype()->IsNull())
> // yes.
>
> But, thing->IsObject() breaks down with this test, which would theoretically
> look like this:
>
> if (thing->IsObject() && thing->GetPrototype()->IsNull())
> // yes.
>
> Since Object.create(null) will also pass this test. Is there something else
> I could do to determine if this is a Object.prototype? (I can't compare
> because the objects may be coming from different contexts).
The best I can come up with is to look up Object on the global object
with context->Global()->Get(...), then check if its .prototype
property StrictEquals |thing|.
It's not 100% foolproof because someone can override the built-in with
`Object = {}`. You could look it up when creating the context and
keep a reference in a v8::Persistent.
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