Hello all!
First, thanks Matt for your reply to my last question, you've
always been a big help, and I appreciate your time sacrificed to help
me.
This question may be off topic for this forum, so Shawn I
apologize in advance, but the participants here represent a knowledge
pool I would be hard-pressed to find elsewhere.
I am working on a new job and basically have had to acquire an
old tape drive to write the data to for transport to the customer.
My experience with computing goes back to the early 80's, but this
has been a new experience for me. When writing data to this drive,
parameters selected include things like block length, record length,
etc. I thought I did pretty well in educating myself and getting it
all set up properly.
The customer can't read the tape because of this
error: "Internal block length of file does not agree with external
block length."
I am interpreting this to mean the block length of the data on
the tape, which I set to represent 25 records of 275 bytes, does not
correspond with what they are expecting to read. Which they say the
block length for 25 records is preferred.
I am reading the data from a file off a cd which has the 275
byte records. These records have a CR/LF at the end of each record.
I am thinking perhaps the CR/LF is causing a problem, but I thought
if I read a 275 byte record, the software (NovaXChange) would know
the CR/LF is not part of the record itself and would strip that if
necessary when transporting the data to the tape, which I configured
as no label (filenames), 275 byte records at a fixed block length.
I know this is a shot in the dark, but thought maybe some of you
might have some experience with these older tape systems and help me
understand what I might be doing wrong. I know that the customer
specified a density of 85,000 BPI, and the drive we have is less than
half that, and I think that's the problem, but really have no way of
knowing. We can get another tape drive, but I am a victim of some
pressure that's trickled down to me to get this problem resolved. As
usual, I am expected to come up with the solution without the proper
equipment and resources I need. LOL.
Thanks in advance,
Chris
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