Using a simple change to Tim Chase' original substitution response, you
have:
[snip]
if you don't want to type it in every time,
:vmap <C-I> :s/\d\+/\=line('.')-line("'<")<CR>
which adds ctrl-i as a key in visual mode to do the job.
Ok, one last question on this. :-)
Is there a way to start this from where the cursor is and end with the first
non-matched instance? For example,
char[] str = null;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
int i = 0;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
So, if the cursor is on the first bla.* the first 6 lines will be numbered
sequentially and stop there. Is this possible?
Well, if you have the above mapping, you can then map
:nmap <f4> vip<c-i>
which will visualize the block in question and then reduce the
problem to the previously solved problem.
If you plan to then expand this to auto-numbering blocks
throughout your your document, you might try something like
(broken into multiple lines for easy reading, but would be all
one mappable line)
:g/bla\.blah\.blahh\[\d/if
getline(line('.')-1)=~'blah\.blah\.blahh\['
| let counter = 0
| endif
| s/blahh\[\zs\d\+/\=counter/
| let counter = counter + 1
I haven't tested it (so there's likely some escaping I got
wrong), but it should do similar to my previous mapping, only
when the previous line doesn't match the target pattern, it
resets the counter to zero. It might be reducable to something like
:g/.../if getline(line('.')-1) =~ @/
which might be a little easier to read/understand, as it uses the
search register.
Just a few ideas.
-tim
