> I would like to count number of character ; I have at the beginning of
> a line like that :
> ;;foo;bar;;
>
> I want a count = 2 but this command returns 5.
>
> :.s/;/&/gn
I'm not sure I quite understand what you want, but you might be
able to hack something with \= like
:%s/^;*/\=strlen(0).' '.submatch(0)
which will count just the ";" at the beginning of the line and
put that count there. If you need the count in a variable
instead of on the line, you could do something like
:echo strlen(matchstr(getline('.'), '^;*'))
If you wanted to count all the ";" on the line, you could do
something more complex like:
:%s/^.*/\=strlen(
substitute(submatch(0), '[^;]\+', '', 'g')
).' '.submatch(0)
(broken to make it easy to read, but should be all one line)
Hope this helps,
-tim
--~--~---------~--~----~------------~-------~--~----~
You received this message from the "vim_use" maillist.
For more information, visit http://www.vim.org/maillist.php
-~----------~----~----~----~------~----~------~--~---
