On 08/20/2011 07:57 PM, ZyX wrote:
Reply to message «Tweaking $ command»,
sent 03:05:13 21 August 2011, Sunday
by AK:
Is there a better way to do this?
0. You said you want just
> to change $ command to go to N chars before the end of line
but what in this case `k' is doing in the second :normal command?
The 'k' was fixing downward movement of $ command. After replacing with
normal! $, it works without that fix.
1. You must not use :normal here (you could replace
exe "normal \<End>"
with
normal! $
): use :normal! (with bang).
2. :h map-<expr>:
nnoremap $ "<Bar>$".((v:count>1)?(((v:count-1).'h'):(''))
That doesn't work for me, using vim 7.3 (even after adding the ')').
However, I prefer the function version because it's more readable.
Why is<c-u> needed there?
Try typing `2:', then read a paragraph before :h function-range-example (second
paragraph in :h :call).
I see, but <c-u> seems like a pretty bad kludge. I remember using it at
least a couple of times before, and I still did not remember it because
it's pretty counter-intuitive. I think it would be better if there was
an arg to *map to turn it off, like <no-prepend-range>, because users
would look into *map arguments help for explanation of this behaviour.
If I
remapped $, why does it keep trying to do built-in $ handling of count?
Because v:count is reset each time normal-mode command is executed. Guess why in
> exe "normal \<End>"
command is called *normal*?
That doesn't seem reasonable, why should Vim assume the count applies to
the first (of possibly dozens) normal command in a function?
Is this sort of questions ok to bring up on vim-use list?
Anyway, thanks a ton for your help and here's what I ended up with if
anyone wants to use this too:
func! EndOfLine()
" Go to Nth char before end of line
normal! $
if v:count | exe "normal ".v:count."h" | endif
endfu
nnoremap $ :<c-u>call EndOfLine()<cr>
-ak
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