Am 07.11.2011 15:08, schrieb Axel Bender:
@Andy
Thanks for the answer!
The split on '\zs' was new to me. Made some speed tests and found
that for lines with more than 180 chars the first solution is faster,
and for shorter lines the solution below, which is based on the
split() approach. Opted for the new solution as short lines are much
more common.
function! CWord(string, class_start, class_end)
let l:chars = split(a:string, '\zs')
let l:len = len(l:chars)
let l:pos = virtcol(".") - 1
Using virtcol() looks wrong
let l:start = l:pos
while l:start>= 0&& l:chars[l:start] =~ a:class_start
let l:start -= 1
endwhile
let l:end = l:pos
while l:end< l:len&& l:chars[l:end] =~ a:class_end
let l:end += 1
endwhile
return join(l:chars[l:start + 1:l:end - 1], '')
endfunction
A few more hints ...
Are you aware of
:echo expand("<cword>")
:echo expand("<cWORD>")
:h expand()
If you just expect 'iskeyword' characters for the identifier (or
whatever you try to match), then
:echo expand("<cword>")
will do.
You can distinguish between possible start and end characters:
:echo matchstr(expand("<cword>"), '\h\w*')
(not perfect, but will do in *most* cases)
Or use a custom 'isk' setting, just for the matching:
func! CWord1(custom_isk)
let sav_isk = &isk
let &l:isk = a:custom_isk
let word = expand("<cword>")
let &l:isk = sav_isk
return word
endfunc
Just a few hints ...
I'd never loop over characters in Vimscript if possible.
--
Andy
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