On 9/19/20 3:13 PM, Tim Chase wrote:
My assumption was that "aaa" was a meta-regex that matched whatever
was needed, including any word-boundaries or other matching/context
the OP needed.
That seems like a reasonable assumption. Thank you for clarifying.
Depends on what you mean. There are multiple regex in play:
- the thing looked for in the g/first/
This first one is what I had in mind when I asked the question.
- the boundary looked for when looking backwards (empty line or BOF)
- the boundary looked for when looking forwards (empty line or EOF)
- the thing looked for in the s// command
This is actually where I was wanting to use the contents of g/first/. ;-)
Using the :norm method, you don't have the two boundary regexen to
change the most-recently-used-search, so the regex in the :g can be
preserved into the :s// command so you don't have to duplicate it.
If I'm understanding you correctly, the following regex could be used:
:g/aaa/?^$\|\%^?,/^$\|\%$/s::bbb:g
Either way, whatever regex the :s// searches for can capture all (for
replacement with "&") or subsets (with "\(…\)" for replacements
with "\1" through "\9"), and then use those captured bits in the
replacement.
I keep forgetting that & matches the full capture.
Including if you use the :norm method and capture them in the :g
portion. Here I look for "G" followed by any number of "C"s followed
by another "G" and then replace them with a "T" followed by the
"C"s we captured, followed by another "T":
:g/G\(C*\)G/norm vip:s//T\1T/g^V^M
This seems like the typical subset mentioned above used in conjunction
with the "last search pattern" (nomenclature?).
Thank you Tim. As always you make it easy to learn new things. :-)
--
Grant. . . .
unix || die
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