Hi, Getting this awfull string containing several carriage return, seome of them would to be substitute with *space*, seome others with *nothing*.
0.003^@99,"0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0", "0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0" ,0.0,0.0,0.0,0.0001,0.003^@ Using atom, I search and fix part of string where carriage return need to be replaced by space : this is the atom pattern \zs,"[^"]\+"\ze How to only substitute on these focused part of string ? Thank you N i c o l a s -- -- You received this message from the "vim_use" maillist. Do not top-post! Type your reply below the text you are replying to. For more information, visit http://www.vim.org/maillist.php --- You received this message because you are subscribed to the Google Groups "vim_use" group. To unsubscribe from this group and stop receiving emails from it, send an email to vim_use+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/vim_use/ba410108-91e7-45ce-8327-f8b1d3860a34n%40googlegroups.com.
