Thanks !

Le dimanche 18 décembre 2022 à 14:39:23 UTC+1, xigb...@gmail.com a écrit :

> *:s/\zs"[^"]\+"\ze/replace_string_here/g*
>
> On Sun, Dec 18, 2022 at 11:55 AM N i c o l a s <niva...@gmail.com> wrote:
>
>> Hi,
>>
>> Getting this awfull string containing several carriage return, seome of 
>> them would to be substitute with *space*, seome others with *nothing*.
>>
>> 0.003^@99,"0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0",
>> "0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0^@0;0;0"
>> ,0.0,0.0,0.0,0.0001,0.003^@
>>
>> Using atom, I search and fix part of string where carriage return need to 
>> be replaced by space : this is the atom pattern \zs,"[^"]\+"\ze
>>
>>
>> How to only substitute on these focused part of string ?
>> Thank you
>> N i c o l a s
>>
>>
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