Hi Steven,
answering the last question seems to be a good way to put all together
in a simpler way so let's back on your clever pseudocode, I'll add
comments on this.
Short anwser is:
* ArgIndent does exactly what your pseudocode expects
* you need *both* 'ci and 'ai to be turned on
* CTRL_D and CTRL_T is the way to increment/decrement manually
in insert mode. >> and << in normal mode.
Long anwser: inoremap \<cr> to ArgIndent does exactly what your
pseudocode want but in a different way
> if (Enter is pressed after a single backslash)
=> inoremap \<cr>
> preserve the indentation and alignment of the previous line
=> 'ai and 'ci must be set
> * go to new line
> * add spaces to align to the second word in the previous line
> # word: anything that is not white space
let's rewrite ArgIndent in vim9script and add comments
command -nargs=0 ArgIndent {
y | put # yyp in normal mode # stage 1
s!\v^\s+\zs(\S+\s+).*!\=repeat(' ', 1 + len(submatch(1)))!
}
at the end of the stage 1, we have
this --example \
this --example \
and we want to remove 'this' which is a substitution from
this
\v^\s+\zs(\S+\s+).*
to this
\=repeat(' ', 1 + len(submatch(1)))
in details:
\v # use "perlish/extended" regexp syntax
^ # the begin of the line
\s+ # at least one space|tab|nbsp
\zs # start matching there
# so previous chars will remain untouched
(\S+\s+) # capture a word "\S+" and the spaces after "\s+"
. # then the rest of the line
so in
this --example \
* 'this' is the word (submatch(1))
* '--example \' is the rest of the line
so the matched section is 'this --example \' and we replace it by
as many spaces as chars in in the word + 1
1 + len(submatch(1))
=> 1 + len("this")
=> 1 + 4
=> 5
repeat(' ', 5 )
=> ' '
so
this --example \
becomes
--example \
don't hesitate to ask if I wasn't clear.
regards
--
Marc Chantreux
Pôle CESAR (Calcul et services avancés à la recherche)
Université de Strasbourg
14 rue René Descartes,
BP 80010, 67084 STRASBOURG CEDEX
03.68.85.60.79
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