Hi,
I am using Virtuoso opensource v7.2.4. I found that SPARQLs with transitive
relationships return partial results. Could you confirm this behavior? Here
are the reproducing ISQL queries.
- Data insertion:
```
sparql
prefix : <http://test.abc#>
prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#>
prefix owl: <http://www.w3.org/2002/07/owl#>
insert IN GRAPH <urn:test1>
{
:class1 a owl:Class .
:class2 a owl:Class .
:entity0 a :class1.
:entity1 a :class2.
:entity2 a :class2.
:entity0 :relation1 :entity1.
:entity0 :relation1 :entity2.
};
```
- Verification of the data
```
sparql
select ?s ?p ?o from <urn:test1> where {?s ?p ?o .};
```
- The problem query
```
sparql
prefix : <http://test.abc>
prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#>
select ?s ?o where {
#?o a/rdfs:subClassOf* :class2. # Only returns a tuple. I think incorrect.
?o a :class2. # returns all the tuples. I think correct.
?s :relation1 ?o.
};
```
If I run the above query, it only returns one pair of ?s and ?o instead of
two pairs of (entity0, entity1) and (entity0, entity1). If I comment out
the transitive line and uncomment the second line, it returns the correct
result with the two pairs. I believe those two queries should return the
same result.
Is this a bug or do I misunderstand something in the SPARQL?
Thank you!
With regards,
Jason Koh
cseweb.ucsd.edu/~jbkoh
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