Correction:
The current transitive relationship is commented out (which returns partial
results) and the line without transitive relationship is uncommented (which
return all results as I expected.)
With regards,
Jason Koh
cseweb.ucsd.edu/~jbkoh
On Fri, May 11, 2018 at 1:56 PM, Jason Koh <jb...@eng.ucsd.edu> wrote:
> Hi,
>
> I am using Virtuoso opensource v7.2.4. I found that SPARQLs with
> transitive relationships return partial results. Could you confirm this
> behavior? Here are the reproducing ISQL queries.
>
> - Data insertion:
>
> ```
> sparql
> prefix : <http://test.abc#>
> prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
> prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#>
> prefix owl: <http://www.w3.org/2002/07/owl#>
> insert IN GRAPH <urn:test1>
> {
> :class1 a owl:Class .
> :class2 a owl:Class .
> :entity0 a :class1.
> :entity1 a :class2.
> :entity2 a :class2.
> :entity0 :relation1 :entity1.
> :entity0 :relation1 :entity2.
> };
> ```
>
> - Verification of the data
>
> ```
> sparql
> select ?s ?p ?o from <urn:test1> where {?s ?p ?o .};
> ```
>
> - The problem query
> ```
> sparql
> prefix : <http://test.abc>
> prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#>
> select ?s ?o where {
> #?o a/rdfs:subClassOf* :class2. # Only returns a tuple. I think
> incorrect.
> ?o a :class2. # returns all the tuples. I think correct.
> ?s :relation1 ?o.
> };
> ```
>
> If I run the above query, it only returns one pair of ?s and ?o instead of
> two pairs of (entity0, entity1) and (entity0, entity1). If I comment out
> the transitive line and uncomment the second line, it returns the correct
> result with the two pairs. I believe those two queries should return the
> same result.
>
> Is this a bug or do I misunderstand something in the SPARQL?
>
> Thank you!
>
>
>
> With regards,
> Jason Koh
> cseweb.ucsd.edu/~jbkoh
>
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