Bob,
 
Do you need to take into consideration the fact that a small gap exists between 
the outer furnace and the inner core tube?  Is the contact good enough to limit 
the thermal resistance of this space?  Any heat power flowing through that path 
would cause a rise in temperature of the core.
 
 I bring this up just as to point out possible differences between the dog bone 
and the other experiments.

Dave
 
 
-----Original Message-----
From: Bob Higgins <[email protected]>
To: vortex-l <[email protected]>
Sent: Wed, Dec 31, 2014 5:31 pm
Subject: Re: [Vo]:The MFMP replication effort live on youtube.


The dogbone is essentially a tube furnace.  The fuel is placed in a separate 
alumina tube with one end molded closed and having a 4mm bore (like Lugano) 
that is sealed with an alumina plug.  This tube with the fuel is called the 
reaction tube and is about 1/4" in diameter and 8" long.  The reaction tube 
slides inside the dogbone "tube furnace".  There is no hydrogen diffusing to 
cooler regions.  The whole reaction tube is about the same temperature through 
its radius.  There are no steep temp gradients as far as the fuel is concerned. 
 The reaction tube can be removed, replaced with a dummy, or replaced with 
another reaction tube with a different experimental fuel.



On Wed, Dec 31, 2014 at 3:19 PM, Bob Cook <[email protected]> wrote:


Dave and others--
 
The temperature gradient in the dog bone--center to outside-- should make a 
difference in the concentration of hydrogen and other volatile/mobile species 
like lithium.  They would tend to condense in the outer parts of the dog bone.  
 
If Ni is volatile like Higgins thinks it may be, then its availability for 
reaction may be curtailed in a steep temperature gradient. 
 
 Also if thermal agitation of the matrix is important at certain resonant 
frequencies, steep temperature gradients would tend to limit the volume of the 
matrix available for a reaction to be initiated.  If there is such a entity as 
a thermal proton (like thermal neutrons in a fission reactor) then the 
temperature may be important in establishing the interaction cross section 
cross section of the proton with whatever it reacts.  Rossi's negative 
temperature coeff. may reflect this effect of the changing frequency of the 
protons as a function of their temperature or kinetic energy.  Li atoms may 
also be involved with changing frequencies as a function of the local 
temperature. 
 
(In the case of a neutron in a reactor, the kinetic energy of the neutron is 
what changes it interaction cross section with Uranium.) 
 
Bob Cook
  
----- Original Message ----- 
  
From:   David   Roberson 
  
To: [email protected] 
  
Sent: Wednesday, December 31, 2014 10:09   AM
  
Subject: Re: [Vo]:The MFMP replication   effort live on youtube.
  


Jed, The setup   used by MFMP uses the surrounding room temperature as the sink 
for heat   generated within their device.  That should appear cooler to the 
actual   heat generating device than a water cooled metal container which is at 
  approximately 100 C.

I would also believe that convection currents   would be more effective in open 
air rather than confined to a constant 100   degree temperature enclosure.

I am assuming that there is little direct   conduction between the active 
device and the metal container in Parkhomov's   experiment.  Are you aware of 
any attempt to conduct heat directly   away?

Dave
  


  


  


  
-----Original   Message-----
From: Jed Rothwell <[email protected]>
To:   vortex-l <[email protected]>
Sent: Wed, Dec 31, 2014 10:06   am
Subject: Re: [Vo]:The MFMP replication effort live on youtube.

  
  
  
  
Bob Higgins <[email protected]>   wrote:
  

  
    
Based on analysis of Lugano and Parkhomov work, excess heat     begins at about 
950C.  The MFMP dogbone core was measured to be over     1200C and no excess 
heat was found.
  


  
As I said, I have a feeling that is too hot. I think the Lugano   temperature 
may have been lower than they thought. I trust Parkhomov's   temperatures, 
which I think were lower.
  


  
Parkhomov's reactor loses heat rapidly with water cooling. Could it be   that 
the temperature difference between the inside and the cooler outside   plays a 
role? This is mere speculation.
  


  
- Jed
  









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