In reply to Eric Walker's message of Fri, 2 Jan 2015 23:36:57 -0800: Hi, [snip] >Have I missed something important? > >Eric
Something else I just thought of: 17O+6Li => 16O + 7Li + 3.107 MeV This reaction would provide a path for Li7 to be regenerated from O17 in the Al2O3. The same mechanism that enabled the transfer of a neutron from Li to Ni could also enable this regeneration transfer. 0.037% of O is O17, so 450 gm of Al2O3 would contain about 3E21 O17 atoms allowing for the regeneration of another 3E21 Li7 atoms. This process would, optimistically, quadruple the amount of Li7 available, and also add considerable energy to the process. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
