In the nuclear industry, there is a reactor type called the pebble bed reactor. That reactor uses a uranium and plutonium nuclear fuel enclosed in a graphite and Silicon carbide coating called TRISO fuel.
http://www.intechopen.com/books/metal-ceramic-and-polymeric-composites-for-various-uses/composite-materials-under-extreme-radiation-and-temperature-environments-of-the-next-generation-nucl That pebble bed fuel has been tested to keep all the products of fission sequestered for years at a 100% reliability rate. The same type of barrier element sequestering system could be used to keep the Hot Cat type reactor element tight. The down side is that carbon has been shown to be a poison to LENR in some LENR reactors. Care in the design of the TRISO LENR reactor who be required. >From the analysis of the fuel mix in the Rossi reactor, carbon was found in a high concentration. I take this as an indicator that carbon is being used in the Hot Cat as a hydrogen barrier material. I would put the graphite and SIC element barrier on the outermost serface of the Hot Cat in my own reactor design. On Mon, Jan 5, 2015 at 9:00 PM, <[email protected]> wrote: > In reply to Axil Axil's message of Mon, 5 Jan 2015 17:58:58 -0500: > Hi, > [snip] > > Providing that a graphite coat would actually perform this function, it > could be > a good idea. > > >What if a coat of graphite was applied to the outside of the HotCat as a > >hydrogen barrier during its fabrication and then a final thin veneer coat > >of alumina cement completes the fabrication by covering the graphite and > >forming the heat radiating fin structure. > > > >The hydrogen could permeate throughout the alumina body of the remote not > >being confined until the hydrogen hit the graphite coat on the outside of > >the HotCat. > > > >This method of fabrication would allow hydrogen to get into all of the > >porous alumina structure throughout the entire HotCat reactor. > > > >This would allow much more Oxygen 17 by many orders of magnitude to be > made > >available to the nuclear reaction under discussion. > > Note that in my calculations here below, I already assumed that all of the > O17 > in the Alumina was used. That's why I said it was optimistic. > > > > >On Mon, Jan 5, 2015 at 5:08 PM, <[email protected]> wrote: > > > >> In reply to Eric Walker's message of Fri, 2 Jan 2015 23:36:57 -0800: > >> Hi, > >> [snip] > >> >Have I missed something important? > >> > > >> >Eric > >> > >> Something else I just thought of: > >> > >> 17O+6Li => 16O + 7Li + 3.107 MeV > >> > >> This reaction would provide a path for Li7 to be regenerated from O17 in > >> the > >> Al2O3. > >> > >> The same mechanism that enabled the transfer of a neutron from Li to Ni > >> could > >> also enable this regeneration transfer. > >> > >> 0.037% of O is O17, so 450 gm of Al2O3 would contain about 3E21 O17 > atoms > >> allowing for the regeneration of another 3E21 Li7 atoms. > >> > >> This process would, optimistically, quadruple the amount of Li7 > available, > >> and > >> also add considerable energy to the process. > >> > >> Regards, > >> > >> Robin van Spaandonk > >> > >> http://rvanspaa.freehostia.com/project.html > >> > >> > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
