I wrote:
| With this LAH mass, the Ideal Gas Law Maximum Pressure comes out as 8388
psi,
| and using the van der Waals equation of state, approx. 1.07 times that,
or 8976 psi.
I just went thru the van der Waals equation of state calculation, and the
pressure comes
out to be 9641 psi or 15% more (not 8976 psi or 7% more).
The van der Waals Equation of State for this case is:
p[psi] = 14.6959488 psi + ((wR(T+273.15)) / (v-wb)) – a(w/v)^2
where
R = 0.06355261 [ml][psi] / ([K][mgLAH])
a[H2] = 0.0099592 [ml^2][psi] / [mgLAH^2]
b[H2] = 0.001402 [ml] / [mgLAH]
and the parameters specific to this experiment/test are:
w = 105 mgLAH
v = 1.06 ml
T= 1057 C
Mark Jurich
