With two reactors in series it is easy to compute the resistence of each reactor. One just need to measure the current, which is the same for both reators, and the voltage on each reactor. I would be very much surprised if the resistence of the Khantal A-1 wire changes more than that on its specs ( http://kanthal.com/en/products/material-datasheets/wire/resistance-heating-wire-and-resistance-wire/kanthal-a-1/). But even if this happens (which would be very interesting to investigate), it would not negatively affect the hypothesis test.
Alberto. On Sat, Mar 21, 2015 at 2:19 AM, Axil Axil <[email protected]> wrote: > In the Lagano experiment, the resistance of the heater decreased to one > third of its initial startup value. Riddle that one batman. > > On Sat, Mar 21, 2015 at 1:33 AM, Alberto De Souza < > [email protected]> wrote: > >> Hi Bob, >> >> On Fri, Mar 20, 2015 at 9:21 PM, Bob Cook <[email protected]> >> wrote: >> >>> Alberto-- >>> >>> You are correct that voltage and current gives integrated power in the >>> section of the coil between the voltage drop measurements. However, if >>> your are interested in local power generation in the active region where >>> the fuel is, you need to know the resistance in that region and hence its >>> temperature together with the current to determine power applied to the >>> fuel. >>> >> >> Actually, the resistence of heating wires varies very little with >> temperature. In the case of Kanthal A-1 (that MFMP was using), it increases >> by a factor of only 5% from 100 to 1400 degress Celsius (see >> http://kanthal.com/en/products/material-datasheets/wire/resistance-heating-wire-and-resistance-wire/kanthal-a-1/). >> So, considering a high COP (3), this control-variable variance (the wire >> resistance in the reactors) is negligible. >> >> Alberto. >> >> >>> Bob >>> >>> >> >
