Here is how heat energy is transformed in a chain into an electron. Heat
Heat produced dipole motion of an electron formation of a spin based soliton where many electrons circle a vortex.(aka SPP) Projection of a magnetic anapole beam from the center of the electron vortex(SPP) at over 140MeV in strength Formation of a negative meson from the condensation of the anapole magnetic beam via energy to matter by the vacuum. decay of the meson into a pi meson(pion). decay of pion into a mu meson (muon) Muon fusion The dominant muon decay mode (sometimes called the Michel decay after Louis Michel) is the simplest possible: the muon decays to an electron, an electron antineutrino, and a muon neutrino. On Sun, Mar 22, 2015 at 1:08 PM, David Roberson <[email protected]> wrote: > If electrons were the only particle generated the system would assume a > negative charge that continues to increase over time. Most reactions with > electrically neutral particles generate an equal number of positive charged > particles as negative ones. > > The fact that there are no 511 keV gammas suggests to me that no positrons > are being generated during the process. These issues makes the direct > conversion of mesons(unless they are negative initially) into only > electrons not likely in this case. Is there reason to believe that > negatively charged mesons originate during the LENR reaction? > > It appears to me that we need to uncover some technique that allows spin > energy to be directly converted into kinetic energy of atoms without an > associated > significant amount of radiation. Of course the other option discussed > where alphas are generated would allow an effecient transfer of energy to > take place without the very high velocity lighter particles. > > Does anyone know of proof that spin is conserved throughout the system in > a manner that is similar to the conservation of angular momentum? If this > is true then the spin would always be originated as both a positive and a > negative pair during a reaction. One participating particle would acquire > positive spin while another negative so the net spin is zero. The way that > this spin become thermalized remains an interesting question. Bob, do you > have a theory about how this occurs? Or, is my thinking wrong about the > conservation of spin? > > Just my two cents worth. > > Dave > > > > -----Original Message----- > From: Axil Axil <[email protected]> > To: vortex-l <[email protected]> > Sent: Sun, Mar 22, 2015 12:34 pm > Subject: Re: [Vo]:Probability Enhancement via SPP > > A lot of energy could be expended in the creation of electrons as a > final product of meson decay. How can we tell if the LENR reaction converts > spin into electrons. > > On Sun, Mar 22, 2015 at 12:20 PM, Jones Beene <[email protected]> > wrote: > >> Bob, >> Spin could be heavily involved, as would be expected with SPP - but there >> is >> no valid physical model for complete conversion of kilowatts of power >> into >> only spin, as you seem to suggest. If there was, then that avenue is >> certainly more elegant. Since we have no guidance from Physics for >> complete >> conversion to spin - I am trying to fit this phenomenon into a framework >> where there is an accepted model (even if not widely known). >> At the same time, good evidence is turning up that there is a large QM >> anomaly for lithium-6 leading to fusion with the ash consisting solely of >> helium. These are fast particles, even if less energetic than expected in >> hot fusion, and that amount of kinetic energy cannot easily show up as >> only >> spin. >> http://xxx.tau.ac.il/pdf/1503.05266.pdf >> The main problem being one of a complete absence of bremsstrahlung... >> (there >> are no gammas from the start in the reaction, so we do not have to deal >> with >> that problem). This is a bit different from Hagelstein's hypothesis, >> where >> he is struggling to downshift gammas to phonon vibrations - where the >> coupling spans 9 orders of magnitude with complete certainty and no >> leakage. >> With a coherent S-matrix of superradiant coherent IR photons, the problem >> is >> reduced to 4 orders of magnitude, where physical evidence does exist for >> the >> coupling premise (albeit not complete). >> From: Bob Cook >> Jones-- >> >> There is no bremsstrahlung because there are no particles emitted with >> high >> kinetic energy--only quantum spin energy is involved. >> >> Bob >> ----- Original Message ----- >> >> Wiki has a superficial entry for quantum probability >> http://en.wikipedia.org/wiki/Quantum_probability >> and a more complete entry for S-Matrix >> http://en.wikipedia.org/wiki/S-matrix >> The crux of this post is to suggest that the alumina tube reactor operates >> via an enhanced "probability field" favoring a rare nuclear reaction, and >> that the key to this probability enhancement is photonic .... via SPP - >> surface plasmon polaritons. >> Specifically, the premise is that in an intense flux of IR photons, which >> is >> initiated by incandesce, the low probability of a few nuclear reactions, >> especially those involving Li-6, can be enhanced and at the same time >> excess >> energy which is derived can be absorbed by the photonic flux, creating a >> positive feedback parameter. Because the underlying reaction is gamma >> free, >> and the sole component of ash is alpha particles, the missing mechanism >> (for >> now) is the coupling of the 3 alpha emission to the photonic flux (Li6 + >> Li6 >> > 3He). >> From there on, the details of how the expected bremsstrahlung can be >> completely downshifted require "illumination"... but the missing >> mechanism >> may have been hidden in plain view, all along. This premise is easily >> falsifiable. >> More later, >> Jones >> > >
