Your plan seems reasonable to me Jed. Are you convinced that the scientific community will accept it as valid? If that hurdle is overcome then this technique would appear plausible in the quest to prove LENR.
Dave -----Original Message----- From: Jed Rothwell <[email protected]> To: vortex-l <[email protected]> Sent: Mon, Jun 15, 2015 4:17 pm Subject: Re: [Vo]:The good, the bad and the ugly David Roberson <[email protected]> wrote: Jones, I am concerned that no one has been able to overcome the claims of skeptics that liquid water escapes with the steam and therefore confuses the measurement. We need to come up with a dummy proof method that ensures that the steam leaving the system is pure. This is easy to do. First, you use a conventional teapot shape (or chemical retort) with a long spout at the top if the vessel, with the spout pointing up. That eliminates nearly all droplets. That is why people have been making teapots in that shape for thousands of years. You can confirm that droplets do not fall out of the steam by putting a tissue near the spout. It will not get wet. Second, you boil some water with known input power from a joule heater. You measure the water lost. If the lost water exceeds the amount that should have boiled away, you know that droplets are escaping and the shape of the spout is wrong, or the position of the spout is wrong. You should see considerably less than the heat of vaporization (2260 J/g) predicts. That is because the pot walls gets hot, so the heat escapes without boiling the water. That's okay; you can measure the ratio. Later on, while doing the cold fusion experiment, apply this ratio and assume that any additional boiling above the ratio is caused by excess heat. Or, be conservative, you say that only the heat lost to boiling counts. For reference, electric tea kettles have the heating element inside at that bottom. They are around 80% efficient, which is better than any other kind of kettle, such as gas or electric range, or a microwave. With an uninsulated metal reactor that is about the highest efficiency you can expect. The main thing is to confirm that with a joule heater the reactor does not magically exceed the heat of vaporization. With any vessel resembling the shape of a conventional teapot or retort, it won't. - Jed
