In reply to Axil Axil's message of Fri, 17 Jul 2015 01:17:15 -0400: Hi, >How does your wonder particle stop at neutron formation just at Ni62? [snip]
I previously posted the following to Vortex on Oct. 9 2014, but can't get the archive to show me posts for 2014. _____________________________________________________________________________ In reply to Jones Beene's message of Wed, 8 Oct 2014 09:22:13 -0700: Hi, [snip] Li7 + Ni58 => Ni59 + Li6 + 1.75 MeV Li7 + Ni59 => Ni60 + Li6 + 4.14 MeV Li7 + Ni60 => Ni61 + Li6 + 0.57 MeV Li7 + Ni61 => Ni62 + Li6 + 3.34 MeV Li7 + Ni62 => Ni63 + Li6 - 0.41 MeV (Endothermic!) This series stops at Ni62, hence all isotopes of Ni less than 62 are depleted and Ni62 is strongly enriched. I have only briefly skimmed the report, but the basic reaction appears to be a neutron transfer reaction where a neutron tunnels from Li7 to a Nickel isotope. The excess energy of the reaction appears as kinetic energy of the two resultant nuclei (i.e. Li6 & the new Ni isotope), rather than as gamma rays. Because there are two daughter nuclei, momentum can be conserved while dumping the energy as kinetic energy in a reaction that is much faster then gamma ray emission. Because both nuclei are "heavy" and slow moving, very little to no bremsstrahlung is produced. There is effectively no secondary gamma from Li6 because the first excited state is too high. (I haven't checked Li7). There is unlikely to be anything significant from Ni because the high charge on the nucleus combined with the "3" from Lithium tend to keep them apart (minimum distance 31 fm). It would be nice to know if the total amounts of each of Li & Ni in the sample were conserved (I'll have to study the report more closely). Regards, Robin van Spaandonk Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
