IMHO hydrno moleules with Li must remain a gas or plasma where the shrunken hydrogen only exists as a function of the surrounding geometry therefore the molecule is free to drift thru the geometry and also provides a disassociating force when the geometry lessens and the contracted hydrogen tries to expand back to normal. I think these molecules can transition between atomic and molecular state repeatedly in an endless reaction when random motion returns some of them to regions where they again shrink.. I think the molecular bond acts as a lynch pin to carry potential energy to different regions where the normal symmetry of an atom transitioning transparently between geometries can become an asymmetry if the atoms form a molecule by discounting the molecular disassociation threshold when the atoms try to expand in opposition the bond. If the reactor temp is already close to that threshold I could see a runaway endless reaction where it takes less energy to disassociate the molecule than energy released upon reforming. Fran -----Original Message----- From: mix...@bigpond.com [mailto:mix...@bigpond.com] Sent: Saturday, July 18, 2015 11:24 PM To: vortex-l@eskimo.com Subject: EXTERNAL: Re: [Vo]:Rossi's theory of the LENR reaction - LiHy4-.pdf
In reply to mix...@bigpond.com's message of Sun, 19 Jul 2015 12:58:59 +1000: Hi, [snip] >In reply to Bob Higgins's message of Sat, 18 Jul 2015 19:57:12 -0600: >Hi, >[snip] >There is very little Li7 in the ash, so the high masses based on Li7 might be >below the detection threshold. >The values for Li + 3 hydrinos can indeed be ruled out as you suggest. >That leaves Li6 + 1 or Li6 + 2 with masses 7 & 8 respectively. >The mass 7 would be masked by Li7 therefore be undetectable. >That leaves the mass 8, which might show up, though in order to catalyze the >neutron transfer reaction a fairly high p value molecule would be needed, and >these tend to have binding energies in the keV for the third Hydrinohydride, so >it's possible that it might be too tightly bound for the ion beam to dislodge >with a sufficient frequency for Li6Hy2 to show up. [snip] I just realized that this explanation is nonsense, as if it were true, then Li6 itself wouldn't show up either. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
