On Dec 22, 2005, at 8:34 AM, Jones Beene wrote:
Bottom line: ...isn't it a bit too coincidental that in carefully
documented experiments, you can come out to nearly "net neutral" on
the energy equation yet - still have lots of tritium? ... what
happend to the excess heat ?
Electron catalysis might explain that - given an assumption or two.
When two deuterons collide and fuse in hot fusion, it takes a lot of
energy. The resulting nucleus has a lot of pent up potential energy,
which ends up released in the form of decay particle energy, or gammas.
If the waveforms of two deuterons tunnel to the locus of an electron,
i.e. the quantum waveforms of two deuterons and a centrally located
electron collapse at the locus of the electron center of charge, then
the resulting nucleus is not energetic. This concept was more fully
described here in 2001. See <http://mtaonline.net/~hheffner/
EcatFusion.pdf>.
Now, supposing T is the final result of the fusion, and no neutron.
We then have:
D + D + e- ---> He* ---> T + P + 2 e-
where here He* here is not really helium at all, and certainly not an
energetic isomer. Within He*, to produce this reaction, there is an
accelerated decay of a neutron, producing a P and e- which have to
leave the nucleus, and some nominal energy. The work to eject the P
and e- is a wash. The work to eject the second electron, the
catalytic electron, further de-energizes the nucleus. There will be
no energetic gamma. Additionally, the ejection of P + 2 e- could be
expected to produce EM radiation, and not all in one high energy
photon, but rather in smaller chunks. The only signatures of this
reaction are thus low order heat and tritium. That's my guess.
Horace Heffner
