Eric-- What about 3 Li-6 going to 3 alphas and 1 D or 1 Li-7 and 2 Li-6 going to 3 alphas and 1 T. Maybe the higher binding energy of the D and/or the T would reduce the high per nucleon energy you are concerned about.
Bob Cook From: Eric Walker Sent: Sunday, September 06, 2015 2:42 PM To: [email protected] Subject: Re: [Vo]:Bob Greenyer's thoughts on what the "cat" and "mouse" are On Sun, Sep 6, 2015 at 4:37 PM, <[email protected]> wrote: This is obvious nonsense. A failed reaction doesn't produce energy, and hence would not produce an energetic proton. I agree. It's one of the reasons I don't like Piantelli's explanation. A more likely scenario is that a reaction that succeeded produced an energetic proton. Possibly from a neutron stripping reaction? Presumably that could be due to deuterium being stripped of a neutron, resulting in a fast proton. But that would not explain the peak at 62Ni in the Lugano results and the lack of significant amounts of heavier nickel isotopes, which might accumulate if deuterium was involved. One thing I was wondering was whether there could be a reaction involving an accelerated 6Li into a 7Li and what the possible daughters might be. Eric
