RE: [Vo]:Bremsstrahlung radiationThe Lead Cave must be nearby (with the scintillator in it) to replicate. If another scintillator is secured, it is quite possible to run it without immediate lead surrounding it, but it will be close to the Lead Cave, I’m afraid (within a couple feet away, tops). Actually, we do not have enough Lead to house two scintillators anyway, at the moment, but I am digressing...
Although a run could be done with the lead and a run could be done without the lead, this would require another experiment and a huge delay in confirmation unless Alan were to duplicate parts ahead of time... Also keep in mind that when it happens, we cannot be near it moving things until we assess it’s safe to do so. We can automate a few things and we will. It is our understanding that if this is NOT an artifact, that we only have one chance to see it during an experiment, unless we master controlling it. Last time, we set a mouse trap and caught a mouse ... This time, we are hoping to watch as the mouse gets caught, with everything we can throw at it. Right now it’s Mouse 4, MFMP 1 (this is GS 5 Series) ... It’s the Bottom of the Sixth Inning and we are about to take our bat. We’re not out of this yet! - Mark Jurich From: Jones Beene Sent: Monday, February 29, 2016 8:19 AM To: [email protected] Subject: RE: [Vo]:Bremsstrahlung radiation From: Eric Walker Ø To play devil's advocate, the hypothetical neutron flux could have produced short-lived beta radioisotopes when they activated something in or near the experiment. Eric, Even without activation - the neutron itself is a beta emitter. Free neutrons have a half-life of about 10 min and are almost gone in 15. The usual beta electron is .78 MeV and is charged so it will not look like a gamma. And there is no evidence of an accelerated decay in a well-investigate field. However, a fraction of free neutrons do produce a gamma ray on decay. This gamma ray is sometimes called “internal bremsstrahlung” but is soft. See: https://en.wikipedia.org/wiki/Bremsstrahlung#Inner_and_outer_bremsstrahlung If Bob’s procedure is to test the ongoing reaction with no shielding and then with shielding, and compare the two - then many of these issues can be resolved. If no shielding gives significantly more counts, then cosmic rays can be blamed. However, my prediction is that no shielding will show fewer, not more gammas. That is especially true if the reaction itself is making muons (the Holmlid effect). IMO - the most important finding which could come out of this next test is to see significantly more gammas in the cave than with no shielding - and to see a variance from inverse square drop-off, when the cave is moved back from the reactor. Lastly, the peaks can be matched with the temperature differential. If a gamma burst is correlated with apparent endotherm, as happened in the last test – then it would be a significant indication that Holmlid is correct. Jones
