Well, this is partly true. Only charged particles will come to rest quickly and generate Bremsstrahlung. Protons, because they are so heavy compared to an electron, must be 1800x the energy of the electron to have the same initial velocity. Then the heavier proton will basically decelerate 1800 more slowly, creating less Bremsstrahlung. Basically for protons you don't see much of any Bremsstrahlung. Mesons would obviously be somewhere between. However, the most Bremsstrahlung is created by the high energy electron.
On Sun, Feb 28, 2016 at 5:58 PM, Russ George <[email protected]> wrote: > The photo of the detector placement has helped to understand this mystery > > As far as 'breaking radiation' aka Bremstrahlung, any form of energetic > particle coming to a halt produces that characteristic signal, whether they > are crazy heavy muons or speeding electrons...or ??? Neutron clusters or > tetraquarks or Rydberg hydrogen perhaps as they are rare but on the cold > fusion flavor of the day menus. > > The present situation with not even a dental x-ray worth of radiation > being observed is one thing as it derives from an infinitely small fraction > of a joule of nuclear activity, if hundreds of joules of cold fusion > nuclear activity are seen in similar x-rays the dose would be multiplied by > a very large number. > > -----Original Message----- > From: H LV [mailto:[email protected]] > Sent: Sunday, February 28, 2016 4:41 PM > To: [email protected] > Subject: Re: [Vo]:Bremsstrahlung radiation > > On Sun, Feb 28, 2016 at 6:44 PM, Jones Beene <[email protected]> wrote: > > -----Original Message----- > > From: H LV > > > >> In the Lugano test dosimeters were used to check for gamma/xray > emissions at more than 50 cm from the reactor... over the 32 day duration > test it looks like the dosimeters didn't record anything above > background... If the MFMP reactor resembles the Lugano reactor why didn't > the dosimeters register any radiation? > > > > > > I may sound like a broken record on this but it is fairly obvious: > remove the lead bricks - the "apparent" radiation goes away. No lead at > Lugano. > > > > The operative difference was the bricks. The lead captures muons which > are documented by the adjoining scintillator as gamma radiation. Some of > the muons are cosmic but some can be produced in the Holmlid effect. > > This can be easily tested next time around: remove the lead - the > apparent radiation goes away. In a thesis which was referenced earlier on > the known muon interaction with lead: > > > > "overall the study has demonstrated that effects such as neutron > > production in Pb shielding from muon interaction is an important effect > in sensitive GRS experiments as the secondary/tertiary neutrons produced > may interact with target nuclei to produce γ-ray events which could not be > accounted for otherwise" > > > > https://webcache.googleusercontent.com/search?q=cache:OzhUEPLFX44J:htt > > ps://researchbank.rmit.edu.au/eserv/rmit:161164/Turnbull.pdf+&cd=11&hl > > =en&ct=clnk&gl=us#87 > > > > This paper might be a good resource so here is a link which displays all > the charts and pictures. > https://researchbank.rmit.edu.au/eserv/rmit:161164/Turnbull.pdf > > It is just my opinion, but I doubt that muons interacting with lead would > be capable of generating the observed the spectrum. > However, couldn't muons and electrons could both generate Bremsstrahlung > radiation? > > harry > > >
