Rather, not easier, but 1MW is not too much 2016-08-15 16:54 GMT-03:00 Daniel Rocha <[email protected]>:
> I think the problem is keeping T0 constant or low. Suppose T0=20C, T1=100, > T2=70 > > 10^6=4^10^2*D*L*(100-60)/(log((100-20)/(70-20))~1.0*10^8 > > D*L~40 > > The higher the energy to be exchanged, the easier is to build the system. > > > > 2016-08-15 13:41 GMT-03:00 Giovanni Santostasi <[email protected]>: > >> So actually the solution for the differential equation of a heat >> exchanger is the following: >> >> dQ/dt=h*D*L*(T1-T2)/log( (T1-)/(T2-T0)) >> > -- Daniel Rocha - RJ [email protected]
