Jones has identified the lack of significant excess heat fro PdD and NiH 
systems.


After 28 years nobody has succeeded in generating 100 watts excess in a 
repeatable process. In fact there is no qualified system that can achieve 10 
watts excess and a COP > 1.5


Perhaps we are trapped in the wrong metaphor. CF requires two miracles:


  1.  D-D fusion
  2.  No radiation

Perhaps a magnetic origin interacting with the vacuum requires less on the 
miracle front.


________________________________
From: Jed Rothwell <[email protected]>
Sent: Tuesday, June 6, 2017 9:44 PM
To: Vortex
Subject: Re: [Vo]:Bose Einstein Condensate formed at Room Temperature

Jones Beene <[email protected]<mailto:[email protected]>> wrote:

No ! You seem to be confusing chemistry with nuclear reactions. Heat is not 
being stored but altered reactants are.

Incorrect. Any method of storing energy -- chemical, mechanical, electrical or 
nuclear -- must result in a heat deficit. All energy converts to heat. Whether 
the heat sources is chemical or nuclear, all of the energy in the end converts 
to heat, and only heat leaves the calorimeter.

Obviously, the heat itself is not stored. I did not say that, and I did not 
mean it.

When you load a hydride, chemical energy is stored -- not heat itself. More 
energy goes in than comes out. There is an energy deficit, and when the hydride 
is inside calorimeter, that shows up as a heat deficit.

When you charge a battery, electricity is stored as a chemical change. Total 
energy leaving the cell is less than energy going in. Because heat is the only 
form of energy a calorimeter can detect, and because all sources and all forms 
of energy must eventually degrade into heat, the calorimeter sees a deficit. 
Other instruments will show the stored energy in other forms. An electric power 
meter attached to the battery will show the stored energy as increased 
potential electricity (voltage or specific gravity), but a calorimeter can only 
measure it as a heat deficit while the battery is charged.

Mechanically winding up a spring inside a calorimeter will show a complete heat 
deficit. That is to say, you put work into the spring, but no heat is produced. 
This was a classic 19th century experiment performed by J. P. Joule. This would 
violate the First Law if the energy were not stored in the spring, by changing 
the internal structure of the spring.

https://books.google.com/books?id=oxQ2i23IiMsC&pg=PT67&lpg=PT67&dq=winding+up+a+spring+in+a+calorimeter&source=bl&ots=LkyLjbUQbX&sig=sAFyzKgdgWBLUFo-jKXTQy_TQGs&hl=en&sa=X&ved=0ahUKEwjhg5uCy6rUAhVG4SYKHWysARMQ6AEIKjAC#v=onepage&q=winding%20up%20a%20spring%20in%20a%20calorimeter&f=false

What you are describing would be a violation of the First Law. You cannot store 
energy into a system and not reduce the amount of energy that comes out of the 
system.


The dense deuterium which is created and stored using some of the heat of the 
ongoing reaction can and does react after power is cut.

If dense deuterium is created, and this stores energy, less energy degrades 
into heat, and there is a heat deficit. This does not happen.

- Jed

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