Robin--
Resonances are key IMHO. The photon’s frequency—both electric and magnetic fields, probably the magnetic field is most important---are necessary to exceed the potential binding energy fields of the nucleon to cause it to disintegrate into its constituent quasi- stable free muons and other particles—alphas, neutrinos, electrons and maybe positrons. The same sort of resonance reaction occurs in neutron-nucleus interactions involving transmutations and fission disintegrations. THE NEUTRON RESONANCE FREQUENCY IS A KEY PARAMETER ALLOWING THE RESPECTIVE REACTION. However. The neutron reactions reuqire an additional constraint—linear momentum conservation. That is not an apparent constraint in the photon-nucleon reaction IMHO, only conservation of energy and angular momentum. (I suspect that it will be found that charge is also conserved in the Holmlid reaction.) As far as I know, high energy electron scattering experiments do not cause disintegration of target nucleons always. Bill Stubbs would understand the likely scattering model and could constructively comment on this issue. Bob Cook s. ________________________________ From: [email protected] <[email protected]> Sent: Friday, April 5, 2019 9:10:04 PM To: [email protected] Subject: Re: [Vo]:A backdoor to proton annihilation? In reply to [email protected]'s message of Sat, 6 Apr 2019 03:39:40 +0000: Hi, A minor variation is the possibility that it's the excess positron that is responsible for the stability of the whole proton. If an intruding electron were to annihilate that positron, then the whole proton might lose coherence. However I suspect it's all a it more complicated, because otherwise protons bombarded with electrons would be disintegrating all over the place. [snip] Regards, Robin van Spaandonk local asymmetry = temporary success
