[image: B = \frac{1}{3}\left(n_\text{q} - n_\bar{\text{q}}\right),]
where *n*q is the number of quarks <https://en.wikipedia.org/wiki/Quark>.
Should read
[image: image.png]
On Wed, Apr 24, 2019 at 1:20 PM Axil Axil <[email protected]> wrote:
> In particle physics <https://en.wikipedia.org/wiki/Particle_physics>, the
> *baryon
> number* is a strictly conserved
> <https://en.wikipedia.org/wiki/Conservation_law_(physics)> additive quantum
> number <https://en.wikipedia.org/wiki/Quantum_number> of a system. It is
> defined as
> {\displaystyle B={\frac {1}{3}}\left(n_{\text{q}}-n_{\bar
> {\text{q}}}\right),}[image: B = \frac{1}{3}\left(n_\text{q} -
> n_\bar{\text{q}}\right),]
>
> where *n*q is the number of quarks <https://en.wikipedia.org/wiki/Quark>.
>
> The baryon number is conserved in all the interactions
> <https://en.wikipedia.org/wiki/Fundamental_force> of the Standard Model
> <https://en.wikipedia.org/wiki/Standard_Model>, with one possible
> exception. 'Conserved' means that the sum of the baryon number of all
> incoming particles is the same as the sum of the baryon numbers of all
> particles resulting from the reaction.
>
> The reason why "LLNL not all over this" is because the Holmlid effect
> violates the *baryon number conservation law.*
>
>
> https://en.wikipedia.org/wiki/Baryon_number
>
>
>
>
>
> On Wed, Apr 24, 2019 at 12:04 PM JonesBeene <[email protected]> wrote:
>
>>
>>
>>
>> https://www.researchgate.net/publication/331968180_Ultradense_protium_p0_and_deuterium_D0_and_their_relation_to_ordinary_Rydberg_matter_a_review
>>
>>
>>
>> There is a clue here about why the output in muons has been difficult for
>> others to duplicate.
>>
>>
>>
>> It turns out that the active material must be in the form of long chain
>> clusters, not simply the smaller grouping.
>>
>>
>>
>> QUOTE: “Superfluidity and a Meissner effect at room temperature are only
>> found for the long chain clusters H2N(0), while the small H3(0) and H4(0)
>> clusters do not have any super properties”
>>
>>
>>
>> This means that there is a specific technique which has to be implemented
>> to first densify and then to create the extremely dense clusters in which
>> most of the nuclear reaction processes take place.
>>
>>
>>
>> Following this step, laser irradiation will give meson showers (most
>> types of kaons and pions) and, after meson decay, large fluxes of muons and
>> other leptons.
>>
>>
>>
>> The fluxes can be extraordinarily high
>>
>>
>>
>> Why is LLNL not all over this ???
>>
>>
>>
>> It seems almost negligent to ignore this. Heads should roll if the
>> Holmlid effect has been overlooked by the one National Lab whose missionand
>> multibillion funding level is so similar.
>>
>>
>>
>> Not to mention the military implications.
>>
>
