Robin - No apparent violation there since the baryon number on both sides of the reaction is 0 p+ + p– → γ (gamma ray) + γ (gamma ray)
IOW when the proton and antiproton come into contact, they annihilate into two high-energy photons. [email protected] wrote: Perhaps I misunderstand conservation of Baryon number, but isn't proton : anti-proton annihilation an obvious violation?
