In order to achieve 1.0 kg of weightlessness at the earth's
surface, ~ 20 joules of electrogravity energy (as D.C.) must be stored
between the plate of a vacuum capacitor..
Thus for a pair of one meter square plates separated by 1/2 meter
the voltage V required = (20/8.85e-12)^1/2 = 1.5 Megavolts.
Obviously to get any floating levitation the two plates of the capacitor
must have a combined mass of less than a kilogram.
Sphere-within-a-Sphere capacitors will eliminate ion wind/corona
problems if the radius of the inner sphere (a) is one meter
(to allow occupancy) and the radius of sphere (b) is 1.5 meters
C = 4(pi)8.85e-12/0.5 - 2.22e-10 farad.
The vacuum volume between the spheres is about 36 cubic meters.
The material for the spheres requires 41 square meters of strong-conductive
material. Based on 24 gauge aluminum (~ 1.4 kg/meter^2) the
combined weight of the spheres is about 60 kg.
At 20 joules/meter^3 required to achieve weightlessness it will require
at 1300 joules to float.
V = [1300/(2*2.22e-10)]^1/2 = 3.4 Megavolts
Connecting additional sphere-in-sphere units together using crawl-able
tubes-in-tubes (parallel capacitance at the working voltage) will add to float capability.
TGIF
Anonymous :-)
