In reply to TP Sparber's message of Mon, 19 Jun 2006 15:09:36 -0600: Hi Fred, [snip] >It would take four Deuterons (Deutero-Hydrinos?) or two 2-Helium-4 >atoms to form 59-Prasodymium-141 from a Stable 55-Cesium-133 atom. > >http://www.webelements.com/webelements/elements/text/Cs/isot.html > Consider the following.
A small hydrino attaches to a proton forming a dihydrino molecular ion, which is positively charged, and looks somewhat like a large deuteron. Now look at a He4 nucleus, and notice that it could well be two deuterons side by side, in a flat square with protons in opposite corners (see http://users.bigpond.net.au/rvanspaa/checker.ppt ) - (this allows the protons to be maximally separated). Now just suppose that two hydrino molecular ions can combine in a similar fashion, i.e. side by side with the "protons" in opposite corners. We would have a unit comprising four nuclei and two electrons, i.e. with a net charge of +2, and a mass ~= 4 amu. If we now substitute a real deuteron for each proton, then we have a very small unit with a net charge of +2, and a mass ~= 8 amu. Now let a couple of electrons take up residence around this central structure, and shrink to the point where they are not much bigger than the central unit itself. We now have a unit with a mass ~= 8 amu, and virtually no charge. This little critter could fuse with other nuclei, and would add 8 amu / reaction. Regards, Robin van Spaandonk http://users.bigpond.net.au/rvanspaa/ Competition provides the motivation, Cooperation provides the means.
