As discussed here before, if any or both of the current and voltage is constant 
then power can indeed be measured as simply as you said, otherwise it can't. It 
is a common mistake (or fraud) in overunity claims to pretend that average I 
times average V is equal to average I*V (power) when the signals are both 
time-varying. It is also common to believe (or pretend) that they are constant 
by not looking at them with the right time resolution.

Michel

----- Original Message ----- 
From: "Paul" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Sunday, January 21, 2007 11:03 PM
Subject: Re: [Vo]: Bruce Depalma & "Free Energy


> Michel Jullian wrote:
> > So I understood, but by DC do you mean constant
> value, or just not AC (not zero average) ?
> 
> Constant voltage and current, constant value as you
> put it, with no AC.
> 
> Paul
> 
> 
> 
> 
> > ----- Original Message -----
> > From: "Paul" <[EMAIL PROTECTED]>
> > To: <[email protected]>
> > Sent: Sunday, January 21, 2007 9:06 PM
> > Subject: Re: [Vo]: Bruce Depalma & "Free Energy
> >
> >
> >> Michel Jullian wrote:
> >>> ----- Original Message -----
> >>> From: "Paul" <[EMAIL PROTECTED]>
> >>> To: <[email protected]>
> >>> Sent: Sunday, January 21, 2007 12:36 AM
> >>> Subject: Re: [Vo]: Bruce Depalma & "Free Energy
> >>>>>> The funny think is that the N-Machine is very
> >> very
> >>>>>> easy to test
> >>>> Shhh, don't tell that to Dr. Kincheloe, ***a
> >> Professor
> >>>> of Electrical Engineering!***
> >>>> It's really difficult to read a DC voltage meter
> >> and
> >>>> multiply it by the DC current. ;-)
> >>> If what you're expecting as a result is
> electrical
> >> power, yes it can be tricky at times
> >> :) What did the current and voltage look like on a
> >> scope?
> >>> Michel
> >>
> >> Hi,
> >>
> >> I referring to DC signals.
> >>
> >>
> >> Paul
> 
> 
> 
> 
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