OK Mike, let's say your description is correct. This means that many
chemical combinations are available in the system on a nanoscale. Why
does Mills focus on NaH? In fact, we have no idea what material or
chemical combination of elements is acting as the catalyst. Also, we
have no reason to believe the H goes to H[1/4] even if we accept that
some level of hydrino forms. So, us skeptics can only marvel at Mills
actually creating an energy source even though he can have no
understanding of what is actually happening in the system. His
description is based completely on what he EXPECTS to happen.
Ed
On Oct 23, 2008, at 12:38 PM, Mike Carrell wrote:
----- Original Message ----- From: "Edmund Storms" <[EMAIL PROTECTED]
>
To: <[email protected]>
Cc: "Edmund Storms" <[EMAIL PROTECTED]>
Sent: Thursday, October 23, 2008 1:18 PM
Subject: Re: [Vo]:Banking on BLP?
I'm confused. I was under the impression that the NaH was the catalyst
required to form the hydrino. If this is true, what is the role of the
Reney nickel?
Ed
=========================================
Ed, I share your confusion. The paper "Commercializable...." has
lots of details but doesn't look well organized. As far as I can tell:
1) The R-Ni acts as a catalyst to dissociate H2 input to 2H. It also
absorbs H2, servig as a resivoir.
2) In the BLP paper 0.5% [5 mg] of NaOH is "coated" on the R-Ni.
They only way I know to do this is in solution.
3) Having coated the R-Ni, the cell is evacuated. This will remove
the water, leaving crystalline NaOH dispersed through the R-Ni
4) The evacuated cell is heated. Reactions with the residual Al, the
H , the Na, and the O yield NaH.
5) NaH begins to decompose, with Na now becoming a BLP catalsy for
the proximate H atom. Boom.
6) However, NaH is listed as a catalyst itself, as if it can react
with acailable H atoms captured in the R-Ni.
Mills is quite specific that the only consumable in the cycle is H2,
converted to H[1/4]. All else is regenerated - somehow - in what is
called 'bench chemistry'. I can imagine the Na getting spead all
over the cell during the reaction. I don't know if just opening the
cell and adding water will cause the Na to reaact to produce NaOH
again, or just what. No clues given. [An exercise to left for the
chemist].
Mike Carrell.
