----- Original Message -----
From: "Robin van Spaandonk" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Saturday, October 25, 2008 5:33 PM
Subject: Re: [Vo]:Banking on BLP?
In reply to Mike Carrell's message of Sat, 25 Oct 2008 13:30:19 -0400:
Hi,
[snip]
This is unfortunate given that He+ is also a catalyst.
MC: But He is not a catalyst, it used as a chemically inert heat transfer
medium. When the reaction fires, undoubtedly some He will be ionized and
the
H atoms around, may contribute to the energy yield. That is not
unfortunate,
it is just a sideshow.
The problem is that with He present, and given the temperature at which the
reaction kicks in, it may not be a sideshow, it may the main game.
e.g. suppose that the only role played by the NaH is to supply H atoms, and
that
the actual Hydrino forming reaction is the customary:-
MC. The temperature in the reaction may be very high indeed and someof the
He could be ionized and RT catalysis is possible. The timperature spike is
from a thermocouple in contact with the cell, but not in the heart of the
reaction itelf, where the temperature may be much higher. As hydrinos form,
hydrino cascades can also form, reaching higher energy yields.
Unfortumately, UV spectroscopy for these reactions are not available but BLP
may have them -- this process has been known for possibly a year or more.
H + He+ -> H[1/3] + He2+ 54.4 eV ?
The energy released by the reaction would create extra He+ from H.
How could we tell the difference between this and the mechanism that Mills
is
proposing?
As I see it, the only way is to remove the He altogether and just use H2
itself
as the heat transfer medium.
MC: At present the emphasis is on verifying the process. NaH isn't the only
one in the paper. Wht is important is to choose the best process for
scale-up, including the nature of the "production burner". What BLP had
shown is a batch process that looks clumsy to automate. How you build a
megawatt reactor may be another story to be told another year.
<snip>
Ah, but as a compound those electrons are in place. The riddle here is that
Na in a compound does not appear to manifest the required energy hole.
The entire molecule manifests the energy hole, not a particular atom within
the
molecule, and even then it only does so if the molecule breaks up in a
certain
way.
MC: Quite possibly. I 'm working with models from college chemistry for
engineers which is primitive.
The
molecule may thermally dissociate, with the H taking back it electron.
Where
is the energy to ionize the Na as it separates from the H?
All the energy comes from formation of the Hydrino (108.8 eV worth).
MC: But you get that energy *after* the reaction, not *before*, no?
If Na can act as
a catalyst during the separation with only thermal energy,
No, the Na is not the catalyst, the entire molecule is the catalyst.
then the
"resonant raansfer" phenomenon as used/described by Mills apparently has
new
aspects.
The only *new* aspect is that in this case it is an entire molecule rather
than
an atom or an ion that is acting as the catalyst.
Ignoring this detail, and regarding the H[1/3] rpoduct of the
reaction, then a 'conventional' hydrino catalyst has appeared and can act
with any H around.
Agreed, and Mills even makes use of this to explain the preponderance of
H[1/4].
(If you ask me that's a little far fetched. Disproportionation reactions
should
also produce species other than H[1/4], yet his experiments seem to show
nothing
below this. He explains this with a multipole radiation theory, which IMO is
a
bit weak. IOW if his explanation were valid, then I would still expect a few
examples of e.g. H[1/6].
BTW if anyone's interested I have my own explanation for the preponderance
of
H[1/4].
MC: As I mentioned above, lots of hydrino species could appear, but the
calorimeter is not designed for spectroscopy. That doesn't mean that the
reaction has not been studied apart from calorimetry, but Mills is not
releasing such information.
It still is not
clear to me where the 54.35 eV for ionizing Na to catalyze H comes from.
From the Hydrino as it forms.
Many on the list seem to be trying to split the process up in an attempt to
get
a handle on it. (i.e break the molecule into atoms, then ionize the atom(s),
then look for catalysts.
The very act of attempting to do this "simplification" is responsible for
the
difficulty in understanding (because the pieces are not the catalysts - with
the
possible exception of the H itself). The original hole molecule is the
catalyst.
The hole molecule absorbs 54.35 eV when it breaks up a certain way. Since
54.35
is very close to 54.4 and thus a multiple of 27.2, it is a Mills catalyst.
[snip]
To make a long story short, when the Hydrino forms, part of the energy
released
is stored in chemical form (Na++ etc.) and part is released directly to the
environment. The part stored in chemical form is then shortly (and
separately)
also released to the environment as per equ. 24.
MC: That helps a bit, Robin, but where does the 54.45 eV come from? The
thermal input from the heater does not seem enough, and there is no
ionization field as in the microwave cell. Yet the DSC plot clearly shows
something happening.
The 54.45 is not a "trigger", it's simply what is left over when you
subtract
54.35 from 108.8. IOW it also comes from the shrinkage.
IOW when the shrinkage reaction takes place, 54.35 eV of the 108.8 is used
to
break up the NaH in that "special" way, and the remaining 54.45 eV appears
as
e.g. kinetic energy (or possibly as UV).
I suspect everyone is wondering "so what triggers the reaction" (I certainly
am
;)
[snip]
MC: Thanks again, Robin. You have a better insight into this than I do. My
information source whispered of an "anomaly" discovered some time ago, and I
suspect the DSC plot may have been it. The behviour cedrtainly seems
anomalous. How Mills arrived at this place would make an interesting story
which may be told someday.
Regards
Mike Carrell
