On Nov 15, 2008, at 8:14 PM, Jones Beene wrote:
Hi Robin,
> How then is the electron bound to the proton at all?
..consider: given that a circular "orbit", in QM terms, is an
illusion,
the lack of an apparent binding electrostatic attraction (even if
one did
not agree with Mills) does not necessarily prelude magnetic (or other)
attraction.
The magnetic field of an electron at the Bohr radius is a least
a factor of 1000 times stronger than the electric field, no ?
The electron waveform is co-centered with the proton so one way to
look at it is there is on average no net Coulomb force or magnetic
force on an orbital electron, though there is some degree of spin
coupling between the electron and proton in a hydrogen atom. The
question then becomes where do we actually observe the electron when
we sample for it and what size is it there, what forces should it
have on it there? These are questions having random variables in the
answers.
Looking at this from a Bohr point of view, i.e. the electron
essentially being a point charge with a magnetic moment orbiting the
proton at the Bohr radius, the Coulomb force is 5.149x10^-9 N and the
magnetic force is 3.910x10^-17 N, so the Coulomb force is about 132
million times larger than the magnetic. The dipole magnetic force is
a 1/r^4 force, so can exceed the 1/r^2 Coulomb force at a small
enough radius, but for high energy nucleus plunging electrons only.
Somehow I missed the earlier posts in this thread, but that is to be
expected I guess since I have over 1000 unread vortex messages,
skipped due to lack of time or the hint of religion or politics
somewhere in the associated threads.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
