In reply to Horace Heffner's message of Sun, 12 Jul 2009 19:59:10 -0800: Hi, [snip] >A 100 micron foil weighs 12 g/ >cm^3 * (100x10^-6 cm) = 0.0012 g/cm^2 = 1.2 mg/cm^2. Attenuation in >a 100 micron thick Pd foil, a 1.2 mg/cm foil, would only be on the >order of (0.3 MeV/mg/cm^2) * (1.2 mg/cm^2) = 360 keV.
I get 120 mg/cm^2 which results in an energy loss of 36 MeV, more than enough to stop them. (100 micron is 100x10^-6 m, not 100 x 10^-6 cm). Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html
