In reply to  Horace Heffner's message of Fri, 9 Oct 2009 10:55:10 -0800:
Hi Horace,

I'm afraid I can't make any sense of this at all. Perhaps a specific example
with calculations would make it clearer?

[snip]
>I forgot to note another very strong indication that the ability of  
>the electron to radiate photonic energy is not the primary reason for  
>the change in branching ratios, but rather the deflated energy of the  
>initial result of the wavefunction collapse. In other words there is  
>another indication there is a vacuum exchange of energy upon fusion  
>resulting in an apparent reduced Q of the cold fusion reactions. That  
>indication is the nearly complete lack of evidence of any excess heat  
>or particle emissions from the heavy nucleus fusions, despite large  
>nuclear mass changes. There is plenty of evidence of lattice element  
>transmutation, but little evidence of excess heat.  The reason this  
>is so is that hydrogen fusion adds one positive charge to the  
>nucleus, increasing the bonding of the electron by a factor of two,  
>one unit of which is offset by the electron's kinetic energy, and  
>other unit of which is lost energy due to the added proton.  In the  
>case of fusion of deflated hydrogen with an A proton nucleus, fusion  
>adds A positive charges to the nucleus, increasing the bonding of the  
>electron by a factor of A+1, one unit of which is offset by the  
>electron's kinetic energy, and the other A units of which is lost  
>energy due to the added protons.  The lack of appropriate net energy  
>emerging from the new nucleus can not be due to the photon radiation  
>of the trapped electron.  It has to have been carried off by vacuum  
>transactions, possibly electroweak reactions involving neutral  
>species. This is not a large leap of intuition when you consider the  
>fact that much of the mass of hadrons is not really there, but  
>results from vacuum transactions in which particle pairs, including  
>strange quarks, pop in and out of existence within Heisenberg limits.  
>The nucleus is a hotbed of vacuum transactions, so it requires no  
>stretch of the imagination to expect an internuclear electron to be  
>involved in such transactions.
>
>Best regards,
>
>Horace Heffner
>http://www.mtaonline.net/~hheffner/
>
>
>
Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/Project.html

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