In reply to Jones Beene's message of Mon, 7 Dec 2009 13:40:40 -0800: Hi, [snip] >Robin - I am surprised that you did not mention, as a possibility, some >version of the hydrino - for instance the "deuterino" at very high >redundancy. If in the form of a di-deuterino would have similar properties - >to a neutral alpha particle, no? [snip] I suppose that if the fusion of two deuterons to He4 were to occur very close to a C12 nucleus then perhaps the energy of the reaction might result in the break up of the C12. Something along the lines of
2 x D + C12 => 4 x He4 + 16.6 MeV In which case I would expect to see 4 tracks rather than 3. I can't easily see a dideuterino molecule gaining enough kinetic energy to fission C12. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html
