On 03/21/2010 10:59 PM, Stephen A. Lawrence wrote: > > > On 03/21/2010 07:25 PM, Harry Veeder wrote: >> The capacitor is on the input side. A pick up coil was added later to >> see if it is possible to close the loop and generate OU. > > Interesting. Sorry for my confusion; I didn't watch the videos where he > had no pickup coil (video 4 already had the extra coil, of course). > > Is this circuit, which charges the cap, the same as the diagram you > showed but with the battery snipped out? If so, it's surprising (to me) > that the thing can produce DC on the input side; I don't see an obvious > mechanism for rectifying the signal generator output.
Ah well actually yes I do. Check out a data sheet for the mosfet; here are links to a couple (it's a standard part, available from a number of manufacturers): http://www.datasheetcatalog.org/datasheet/philips/IRF640_S_1.pdf http://www.datasheetcatalog.org/datasheet/SGSThomsonMicroelectronics/mXtvwts.pdf Note that there's an internal diode between the source and drain. With that, the AC signal feeding the circuit, and the inductor in series with the diode and capacitor, it seems pretty reasonable that the SG could charge the input capacitor. > > The same argument still applies, in any case -- the power output of the > signal generator hasn't been measured. Measure that, compare it with > the energy appearing the capacitor and being dissipated in the coil, and > *then* see if it still looks like anything funny is going on. > > Strange coupling is the order of the day when working with AC and coils, > but you should always be able to find the source of the energy which > comes out of the system. If you can't get the books to balance at least > to within the margin of error of the instruments, that's something worth > pursuing. But if power in equals power out (within instrument error) > then the question becomes, "How is the power getting from the input to > the output?", rather than, "Where is the power coming from?". > > "Instrument error" may be pretty substantial when measuring high > frequency AC with out of phase volts and amps, by the way. > > As another aside, you can certainly boost voltage with just a single > coil. Put volts across the coil for a while, allowing the current to > ramp up, then chop off the drive voltage abruptly. Current continues to > flow through the coil, and if the load which the coil "sees" after the > power supply is cut off is high impedence, a large voltage will appear > across the load. This is why, for instance, you can get arcing across > switch contacts when shutting off power to a large electromagnet, even > if you're energizing it with a low voltage source. The fact that the > signal generator which is driving this circuit is apparently making > square waves, not sine waves, is what makes this relevant. > > > >> >> He tried in test 10 but didn't succeed: >> http://www.youtube.com/watch?v=c7CsBr7ouPE >> >> harry >> >> >> >> ----- Original Message ---- >>> From: Stephen A. Lawrence <[email protected]> To: >>> [email protected] Sent: Sun, March 21, 2010 2:51:23 PM Subject: >>> Re: [Vo]:circuit diagram >>> >>> Harry will need to confirm this, but I believe the diagram in >>> question >> is >>> only for the "input" side. The "output" side, which isn't shown, >> consists of a pickup coil, some related circuitry, and >>> the >> aforementioned capacitors. >> >> If I'm wrong, then I'm confused (no >>> great surprise there). >> >> >> >> On 03/21/2010 11:56 AM, Michel Jullian >>> wrote: Wait a minute, I see no cap attached to the output on >>> Harry's diagram "photo 2"discussed here (haven't followed the other >>> discussions), only one capacitor on the input side, in parallel >>> with the battery until the latter is disconnected, which BTW isn't >>> explained on the diagram. Is the diagram not complete? >>> >>> >>> >>> 2010/3/21 Stephen A. Lawrence < >>> href="mailto:[email protected]";>[email protected]>: >>>> >>>> >>>> >>> On 03/21/2010 09:55 AM, Michel Jullian wrote: >>>>> Which >>> voltage? >>>> >>>> Volts on the caps attached to the output -- >>> right, Harry? >>>> >>>> But the signal generator is still hooked >>> up, and it's coupled to the >>>> output (at least) through the gate >>> capacitance of the FET and the linked >>>> inductors of the >>> "transformer", and the signal generator's output power >>>> hasn't been >>> measured or even estimated. So, there's no reason to >>>> believe >>> this rig is doing anything other than transforming and >>>> rectifying >>> the output of the SG. >>>> >>>> As I've already said a boringly >>> large number of times, this is the same >>>> general sort of system as >>> Stiffler's circuit, where he had a signal >>>> generator capacitively >>> coupled to the system, and it was driving a >>>> handful of LEDs. >>> The main innovation here comes from Naudin, and it's >>>> the use of a >>> toroidal coil as the primary with a neo magnet on the >>>> outside of the >>> coil which "twists" the core's field to allow the >>>> toroidal coil to >>> "couple" to the pickup coil. >>>> >>>> >>>> >>>>> >>>>> >>> 2010/3/20, Harry Veeder < >>> href="mailto:[email protected]";>[email protected]>: >>>>>> >>> yes. >>>>>> You are aware that the the voltage keeps rises even >>> after the battery is >>>>>> disconnected. >>> >>> >> >> >> __________________________________________________________________ >> Connect with friends from any web browser - no download required. Try >> the new Yahoo! Canada Messenger for the Web BETA at >> http://ca.messenger.yahoo.com/webmessengerpromo.php >> >
