In reply to [email protected]'s message of Fri, 07 May 2010 09:22:28 +1000: Hi, [snip] Oops, I got this wrong. I used the total energy when I should have used the FWHH, which I don't know, however a rough idea may be obtained by assuming the same ratio of FWHH to total as for the ground state. That yields a FWHH energy of ( 6.8 eV / 91 keV )* 47.6 MeV = 3.6 keV. This in turn yields a half life of 1.8E-19 sec. , during which time light can travel a distance of 0.5 Angstrom. Still not really enough to communicate with the lattice, though it might be enough to "boil off" the local atoms electrons.
>[1] The difference in energy between ground state Be8 and 2 He4 nuclei is just >91 keV, yet even this is sufficient to ensure that the half life of Be8 is on >the order of 1E-16 sec. At 47.6 MeV it should be on the order of 1E-23 sec. In >that time, light can only travel about 4 fm, which gives it no opportunity to >communicate with the rest of the lattice. >Regards, > >Robin van Spaandonk > >http://rvanspaa.freehostia.com/Project.html Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html
